1.5x^2+4.5x+3=0

Solution for 1.5x^2+4.5x+3=0 equation:

1.5x^2+4.5x+3=0

a = 1.5; b = 4.5; c = +3;
Δ = b2-4ac
Δ = 4.52-4·1.5·3
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{2.25}}{2*1.5}=\frac{-4.5-\sqrt{2.25}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{2.25}}{2*1.5}=\frac{-4.5+\sqrt{2.25}}{3}
$